0=(y^2)-9y+18

Solution for 0=(y^2)-9y+18 equation:

0=(y^2)-9y+18

We move all terms to the left:

0-((y^2)-9y+18)=0

We add all the numbers together, and all the variables

-(y^2-9y+18)=0

We get rid of parentheses

-y^2+9y-18=0

We add all the numbers together, and all the variables

-1y^2+9y-18=0

a = -1; b = 9; c = -18;
Δ = b2-4ac
Δ = 92-4·(-1)·(-18)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3}{2*-1}=\frac{-12}{-2}
=+6
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3}{2*-1}=\frac{-6}{-2}
=+3
$